-18x^2-2.8x+1.96=0

Solution for -18x^2-2.8x+1.96=0 equation:

-18x^2-2.8x+1.96=0

a = -18; b = -2.8; c = +1.96;
Δ = b2-4ac
Δ = -2.82-4·(-18)·1.96
Δ = 148.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.8)-\sqrt{148.96}}{2*-18}=\frac{2.8-\sqrt{148.96}}{-36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.8)+\sqrt{148.96}}{2*-18}=\frac{2.8+\sqrt{148.96}}{-36}
$